30n^2+198n+240=0

Solution for 30n^2+198n+240=0 equation:

30n^2+198n+240=0

a = 30; b = 198; c = +240;
Δ = b2-4ac
Δ = 1982-4·30·240
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(198)-102}{2*30}=\frac{-300}{60}
=-5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(198)+102}{2*30}=\frac{-96}{60}
=-1+3/5
$